This means that the MSR (648.83/2) is 324.415. Again, the find the MS error, I divide 71.17 by 5 which gives me a value of 14.23. The F value can be ascertained by dividing the MSR and the MSE. This means that the F value is 324.415 divided by 14.23 is 22.8.
My next step is to compute the F which is 22.8 and then test it using a .05 level to see whether a significant relationship is present. Using a two tail and with a df of 5, my analysis shows that there is a significant relationship because F at 22.8 is greater than the f value with a .05 level at 5.79. I also wanted to determine whether the estimated regression equation provided a good fit. Since the adjusted R square is at 0.862, I can reasonability assert that based on this, the equation does provide a good fit.
My last endeavor is to compute a t-test to determine whether Ho �1= 0 and Ho �2= 0 are significant. The t ratio for �1 is -8.69/1.555= -5.58 and �2 at 13.517/2.085= 6.48. I am seeing if t does equal zero and it is quite obvious that in both cases, the �1 and Ho �2= 0 are significant. This concludes the homework assignment on Simple Linear Regression and Multiple Regression.